Take a random value in the 2^52 range, namely 16^13, i.e. a 13-bit hexadecimal number (because the hash value is hexadecimal, 2^52 === 16^13)6b5124897c3c4 (6b5124897c3c4 equals 1887939992208324 in the decimal system).

Distribute the random value to 0~1, by dividing it by the maximum value of 13 fs, namely 6b5124897c3c4/fffffffffffff. Given the discrete random nature of the hash value, we then can think that any hash value can be transformed into a random number of 0~1 (fffffffffffff is equal to 45035996270496 in the decimal system) 1887939992208324/4503599627370496 = 0.419206889692064.

Make the house edge 1%. Further to calculate 99/(1-X), where X is the random value calculated at Step 2. When X is 0, the result is 99; when X is 1, the result is positive infinite; when X is 0.01, the result is 100; when X is less than 0.01, the result is less than 100.

99/(1-0.419206889692064) = 170.45656748150867

All values less than 100 will be set to 100. In other words, there is a probability of 1% that 100 will appear. Round off the number and divide it by 100 to get the final result.

170/100 = 1.70